Is it mathematically valid for Wolfram Alpha to interpret a^1/b as [math]a^\frac{1}{b} [/math] instead of [math]\frac{a^1}{b} [/math]? Why or why not? - Quora
![sequences and series - Why does Wolfram Alpha give $\sum_{n=1}^{\infty}(e^i)^{n^2}\approx9.92988+1.76807i$? - Mathematics Stack Exchange sequences and series - Why does Wolfram Alpha give $\sum_{n=1}^{\infty}(e^i)^{n^2}\approx9.92988+1.76807i$? - Mathematics Stack Exchange](https://i.stack.imgur.com/DsT4F.png)
sequences and series - Why does Wolfram Alpha give $\sum_{n=1}^{\infty}(e^i)^{n^2}\approx9.92988+1.76807i$? - Mathematics Stack Exchange
![numerical methods - Wolfram Alpha result for infinite series summation . - Mathematics Stack Exchange numerical methods - Wolfram Alpha result for infinite series summation . - Mathematics Stack Exchange](https://i.stack.imgur.com/SP7ft.png)
numerical methods - Wolfram Alpha result for infinite series summation . - Mathematics Stack Exchange
![binomial coefficients - A bug in Wolfram Alpha about an infinite series? - Mathematics Stack Exchange binomial coefficients - A bug in Wolfram Alpha about an infinite series? - Mathematics Stack Exchange](https://i.stack.imgur.com/cwzet.jpg)